WISKUNDE
GRAAD 12
NOG OEFENINGE
Vergelykings : sin = sin, ens.
MATHEMATICS
GRADE 12
MORE EXERCISES
Equations : sin = sin, etc.
NB : As / If dan is al die moontlike oplossings / then all possible solutions are
sin A = sin B
A = B + k . 360° OF/OR A = 180° − B + k . 360°
cos A = cos B
A = B + k . 360° OF/OR A = − B + k . 360°
tan A = tan B
A = B + k . 360° OF/OR A = 180° − B + k . 360°
1. Bepaal die algemene oplossing van die
1. Determine the general solution of the
volgende vergelykings :
following equations :
1.1
sin (6θ − 10°) = sin (5θ − 2°)
1.2
sin (2x − 3°) = sin (x + 19°)
1.3
sin (4θ − 6°) = sin (3θ + 11°)
1.4
cos (2x − 7°) = cos (x + 24°)
1.5
cos (5α − 21°) = cos (4α + 3°)
1.6
cos (4x + 29°) = cos (x − 16°)
1.7
tan (α − 6°) = tan (3α − 44°)
1.8
tan (5θ − 18°) = tan (3θ + 8°)
1.9
cos (2x + 20°) = − cos (x − 11°)
1.10
sin (5x − 10°) = sin (x − 50°)
1.11
tan (7α + 20°) = − tan (3α − 40°)
1.12
sin (3θ − 54°) = − sin (θ + 18°)