WISKUNDIGE GELETTERDHEID
GRAAD 10
NOG OEFENINGE
Waarkynlikheid en kans : antwoorde
MATHEMATICAL LITERACY
GRADE 10
MORE EXERCISES
Probability : answers
1.1 Aantal moontlike uitlomste = 6
en aantal susesvolle uitkomste = 1
1
P(2) = ──
6
[ V 1.1 ]
1.2 Aantal moontlike uitlomste = 6
en aantal susesvolle uitkomste = 1
1
P(5) = ──
6
[ V 1.2 ]
1.3 Aantal moontlike uitlomste = 6
en aantal susesvolle uitkomste = 0
( Daar is geen nulle op dobbelsteen )
0
P(8) = ── = 0
6
[ V 1.3 ]
1.4 Aantal moontlike uitlomste = 6
Ewe getalle op steen = 2, 4 en 6
dus aantal susesvolle uitkomste = 3
3
P(5) = ──
6
1
P(5) = ── . . . vereenvoudig
2
[ V 1.4 ]
1.5 Aantal moontlike uitlomste = 6
Getalle < 4 = 1, 2 en 3
dus aantal susesvolle uitkomste = 3
3
P(5) = ──
6
1
P(5) = ── . . . vereenvoudig
2
[ V 1.5 ]
1.6 Aantal moontlike uitlomste = 6
Ewe getalle < 3 = 4 en 6
dus aantal susesvolle uitkomste = 2
2
P(5) = ──
6
1
P(5) = ── . . . vereenvoudig
3
[ V 1.6 ]
1.1 Total probabile outcomes = 6
and total favourable outcomes = 1
1
P(2) = ──
6
[ Q 1.1 ]
1.2 Total probabile outcomes = 6
and total favourable outcomes = 1
1
P(5) = ──
6
[ Q 1.2 ]
1.3 Total probabile outcomes = 6
and total favourable outcomes = 0
( There are no 8's on a die)
0
P(5) = ── = 0
6
[ Q 1.3 ]
1.4 Total probabile outcomes = 6
Even numbers on die = 2, 4 and 6.
and thus total favourable outcomes = 3
3
P(even number) = ──
6
1
= ── . . . simplify
2
[ Q 1.4 ]
1.5 Total probabile outcomes = 6
Numbers smaller than 4 = 1, 2 and 3.
and thus total favourable outcomes = 3
3
P(even number) = ──
6
1
= ── . . . simplify
2
[ Q 1.5 ]
1.5 Total probabile outcomes = 6
Even numbers greater than 3 = 4 and 6.
and thus total favourable outcomes = 2
2
P(even number) = ──
6
1
= ── . . . simplify
3
[ Q 1.6 ]
3.1 Daar is 52 kaarte in die pak en dus
is totale moontlike uitkomstes = 52
Daar is 4 sesse in die pak en
dus aantal susesvolle uitkomste = 4
4
P(6) = ───
52
1
= ─── . . . vereenvoudig
13
[ V 3. ]
3.2 Daar is 52 kaarte in die pak en dus
is totale moontlike uitkomstes = 52
Daar is 2 rooi sewes in die pak en
dus aantal susesvolle uitkomste = 2
2
P(rooi 7) = ───
52
1
= ─── . . . vereenvoudig
26
[ V 3. ]
3.3 Daar is 52 kaarte in die pak en dus
is totale moontlike uitkomstes = 52
Daar is net 1 9 van klawers in die pak en
dus aantal susesvolle uitkomste = 1
1
P(9) = ───
52
[ V 3. ]
3.4 Daar is 52 kaarte in die pak en dus
is totale moontlike uitkomstes = 52
Daar is 4 Koninginne in die pak en
dus aantal susesvolle uitkomste = 4
4
P(Koningin) = ───
52
1
= ─── . . . vereenvoudig
13
[ V 3. ]
3.5 Daar is 52 kaarte in die pak en dus
is totale moontlike uitkomstes = 52
Daar is 2 swart Konings in die pak en
klawers en skoppens, en dus
die aantal susesvolle uitkomste = 2
2
P(Koning) = ───
52
1
= ─── . . . vereenvoudig
13
[ V 3. ]
3.6 Daar is 52 kaarte in die pak en dus
is totale moontlike uitkomstes = 52
Daar is 2 X 4 rooi prent kaarte in die
pak, diamante en hartens, en dus
die aantal susesvolle uitkomste = 8
8
P(rooi prent kaarte) = ───
52
2
= ─── . . . vereenvoudig
13
[ V 3. ]
3.7 Daar is 52 kaarte in die pak en dus
is totale moontlike uitkomstes = 52
Daar is 2 X 13 swart kaarte in die
pak, klawers en skoppens, en dus
52 - 26 nie swart kaarte en dus
die aantal susesvolle uitkomste = 26
26
P(nie swart) = ───
52
1
= ─── . . . vereenvoudig
2
[ V 3. ]
3.8 Daar is 52 kaarte in die pak en dus
is totale moontlike uitkomstes = 52
Daar is geen geel kaarte in die pak nie
en dus aantal susesvolle uitkomste = 0
0
P(geel kaart) = ───
52
= 0
[ V 3. ]
3.9 Daar is 52 kaarte in die pak en dus
is totale moontlike uitkomstes = 52
Daar is geen rooi 12's in die pak nie
en dus aantal susesvolle uitkomste = 0
0
P(rooi 12) = ───
52
= 0
[ V 3. ]
3.10 Daar is 52 kaarte in die pak en dus
is totale moontlike uitkomstes = 52
Daar is 13 Hartens in die pak
die aantal susesvolle uitkomste = 13
13
P(Hartens) = ───
52
1
= ───
4
[ V 3. ]
3.11 Daar is 52 kaarte in die pak en dus
is totale moontlike uitkomstes = 52
Daar is 2 X 5 = 10 rooi kaarte
kleiner as 7 in die pak en dus
die aantal susesvolle uitkomste = 10
10
P(rooi kaart < 7) = ───
52
5
= ───
26
[ V 3. ]
3.12 Daar is 52 kaarte in die pak en dus
is totale moontlike uitkomstes = 52
Daar is 4 klawer prent kaarte en
dus aantal susesvolle uitkomste = 4
4
P(klawers prent kaart) = ───
52
1
= ───
13
[ V 3. ]
3.1 There are 52 cards in the pack.
and thus total probabile outcomes = 52
There are 4 sixes in the pack.
and thus total favourable outcomes = 4
4
P(6) = ───
52
1
= ─── . . . simplify
13
[ Q 3. ]
3.2 There are 52 cards in the pack.
and thus total probabile outcomes = 52
There are 2 red sevens in the pack.
and thus total favourable outcomes = 2
2
P(red 7) = ───
52
1
= ─── . . . simplify
26
[ Q 3. ]
3.3 There are 52 cards in the pack.
and thus total probabile outcomes = 52
There is only 1 9 of spades in the pack.
and thus total favourable outcomes = 1
1
P(9) = ───
52
[ Q 3. ]
3.4 There are 52 cards in the pack.
and thus total probabile outcomes = 52
There are 4 Queens in the pack.
and thus total favourable outcomes = 4
4
P(Queen) = ───
52
1
= ─── . . . simplify
13
[ Q 3. ]
3.5 There are 52 cards in the pack.
and thus total probabile outcomes = 52
There are 2 black Kings in the pack,
clubs and spades.
and thus total favourable outcomes = 2
2
P(King) = ───
52
1
= ─── . . . simplify
26
[ Q 3. ]
3.6 There are 52 cards in the pack.
and thus total probabile outcomes = 52
There are 2 X 4 red picture cards in
the pack, diamonfs and hearts.
and thus total favourable outcomes = 8
8
P(red picture) = ───
52
2
= ─── . . . simplify
13
[ Q 3. ]
3.7 There are 52 cards in the pack.
and thus total probabile outcomes = 52
There are 2 X 13 black cards in the pack,
clubs and spades and thus 52 - 26
not black cards and thus
total favourable outcomes = 26
26
P(not black) = ───
52
1
= ─── . . . simplify
2
[ Q 3. ]
3.8 There are 52 cards in the pack.
and thus total probabile outcomes = 52
There are no yellow cards in the pack,
and thus total favourable outcomes = 0
0
P(a yellow card) = ───
52
= 0
[ Q 3. ]
3.9 There are 52 cards in the pack.
and thus total probabile outcomes = 52
There are no red 12's in the pack,
and thus total favourable outcomes = 0
0
P(a red 12) = ───
52
= 0
[ Q 3. ]
3.10 There are 52 cards in the pack.
and thus total probabile outcomes = 52
There are 13 Hearts in the pack,
and thus total favourable outcomes = 13
13
P(a Heart) = ───
52
1
= ───
4
[ Q 3. ]
3.11 There are 52 cards in the pack.
and thus total probabile outcomes = 52
There are 2 x 5 = 10 red cards smaller
than 7 in the pack,
and thus total favourable outcomes = 10
10
P(red card < 7) = ───
52
5
= ───
26
[ Q 3. ]
3.12 There are 52 cards in the pack.
and thus total probabile outcomes = 52
There are 4 clubs picture cards
and thus total favourable outcomes = 4
4
P(clubs picture card) = ───
52
1
= ───
13
[ Q 3. ]
4.1 Daar is 30 seuns in die klas en dus
is totale moontlike uitkomstes = 30
Daar is 9 wat sokker speel en dus
dus aantal susesvolle uitkomste = 9
9
P(sokker) = ───
30
3
= ───
: vereenvoudig
10
[ V 4. ]
4.2 Daar is 30 seuns in die klas en dus
is totale moontlike uitkomstes = 30
Daar is 8 wat krieket speel en dus
dus aantal susesvolle uitkomste = 8
8
P(krieket) = ───
30
4
= ───
: vereenvoudig
15
[ V 4. ]
4.3 Daar is 30 seuns in die klas en dus
is totale moontlike uitkomstes = 30
Daar is 9 + 8 + 6 = 23 wat nie rugby
speel nie en dus die aantal
susesvolle uitkomste = 23
OF
Daar is 7 wat rugby speel en dus
30 - 7 = 23 wat nie rugby speel nie
en dus die aantal
susesvolle uitkomste = 23
23
P(nie rugby nie?) = ───
30
[ V 4. ]
4.4 Daar is 30 seuns in die klas en dus
is totale moontlike uitkomstes = 30
Daar is 6 wat nie aan sport
deelneem nie en dus is die
aantal susesvolle uitkomste = 6
6
P(nie sport) = ───
30
1
= ───
: vereenvoudig
15
[ V 4. ]
4.5 Daar is 30 seuns in die klas en dus
is totale moontlike uitkomstes = 30
Daar is 9 + 8 + 7 = 24 wat aan sport
deelneem en dus is die
aantal susesvolle uitkomste = 24
OF
Daar is 6 wat nie aan sport
deelneem nie en dus 30 - 6 = 24
wat aan sport deelneem en dus die
aantal susesvolle uitkomste = 24
24
P(sport) = ───
30
4
= ───
: vereenvoudig
5
[ V 4. ]
4.1 There are 30 boys in the class. and
thus total probabile outcomes = 30
There are 9 that paly soccer and
thus total favourable outcomes = 9
9
P(soccer) = ───
30
3
= ───
: simplify
10
[ Q 4. ]
4.2 There are 30 boys in the class. and
thus total probabile outcomes = 30
There are 8 that play cricket and
thus total favourable outcomes = 8
8
P(cricket) = ───
30
4
= ───
: simplify
15
[ Q 4. ]
4.3 There are 30 boys in the class. and
thus total probabile outcomes = 30
There are 9 + 8 + 6 = 23 that do not
play rugby and thus total
favourable outcomes = 23
OR
There are 7 that play rugby and thus
30 - 7 = 23 that do not play rugby and
thus total favourable outcomes = 23
23
P(not rugby) = ───
30
[ Q 4. ]
4.4 There are 30 boys in the class. and
thus total probabile outcomes = 30
There are 6 that do not play any
sport and thus the total
favourable outcomes = 6
6
P(not sport) = ───
30
1
= ───
: simplify
5
[ Q 4. ]
4.5 There are 30 boys in the class. and
thus total probabile outcomes = 30
There are 9 + 8 + 7 = 24 that do play
sport and thus total
favourable outcomes = 24
OR
There are 6 that do not play sport and thus
30 - 6 = 24 that do play sport and
thus total favourable outcomes = 24
24
P(any sport) = ───
30
4
= ───
: simplify
5
[ Q 4. ]
5.1 Daar is 25 + 18 + 2 = 45 voertuie
geparkeer en dus is die totale
moontlike uitkomstes = 45
Daar is 2 vragotors en dus die
aantal susesvolle uitkomste = 2
2
P(vragmotor) = ───
45
[ V 5. ]
5.2 Daar is 45 voertuie geparkeer
en dus is die totale
moontlike uitkomstes = 45
Daar is 25 motors en dus die
aantal susesvolle uitkomste = 25
25
P(motor) = ───
45
5
= ───
: vereenvoudig
9
[ V 5. ]
5.3 Daar is 45 voertuie geparkeer
en dus is die totale
moontlike uitkomstes = 45
Daar is 18 taxis geparkeer en
dus 45 - 18 = 27 nie taxis nie
aantal susesvolle uitkomste = 27
OF
Daar is 23 + 2 = 27 nie taxis
geparkeer en dus 27 nie taxis nie
aantal susesvolle uitkomste = 27
27
P(nie taxi nie) = ───
45
3
= ───
5
[ V 5. ]
5.4 Daar is 45 voertuie geparkeer
en dus is die totale
moontlike uitkomstes = 45
Daar is 0 busse geparkeer
aantal susesvolle uitkomste = 0
0
P(bus) = ───
45
= 0
[ V 5. ]
5.1 There are 25 + 18 + 2 = 45 vehicles
parked and thus total the
total probabile outcomes = 45
There are 2 lorries and thus the
total favourable outcomes = 2
2
P(lorry) = ───
45
[ Q 5. ]
5.2 There are 45 vehicles
parked and thus total the
total probabile outcomes = 45
There are 25 cars and thus the
total favourable outcomes = 25
25
P(car) = ───
45
5
= ───
: simplify
9
[ Q 5. ]
5.3 There are 45 vehicles
parked and thus total the
total probabile outcomes = 45
There are 18 taxis parked and thus
45 - 18 = 27 non taxi vehicles, thus
total favourable outcomes = 27
OR
There are 25 + 2 = 27 non taxis parked
parked and thus = 27 non taxi vehicles,
total favourable outcomes = 27
27
P(not a taxi) = ───
45
3
= ───
: simplify
5
[ Q 5. ]
5.4 There are 45 vehicles
parked and thus total the
total probabile outcomes = 45
There are 0 busses and thus the
total favourable outcomes = 0
0
P(bus) = ───
45
= 0
[ Q 5. ]
6.1 Daar is 35 leerling in die klas
en dus is die totale
moontlike uitkomstes = 35
Daar is 19 dogters in die klas
en dus is die totale aantal
susesvolle uitkomste = 19
19
P(dogter) = ───
35
[ V 6. ]
6.2 Daar is 35 leerling in die klas
en dus is die totale
moontlike uitkomstes = 35
Daar is 15 leerlinge wat tennis
speel en dus is die totale aantal
susesvolle uitkomste = 15
15
P(tennis) = ───
35
3
= ───
7
[ V 6. ]
6.3 Daar is 35 leerling in die klas
en dus is die totale
moontlike uitkomstes = 35
Daar is 11 - 6 = 5 dogters wat krieket
speel en dus is die totale aantal
susesvolle uitkomste = 5
5
P(dogter + krieket) = ───
35
1
= ───
7
[ V 6. ]
6.4 Daar is 35 leerling in die klas
en dus is die totale
moontlike uitkomstes = 35
Daar is 9 - 3 = 6 seuns wat nie
aan sport deelneem nie
en dus is die totale aantal
susesvolle uitkomste = 6
6
P(seun + nie sport) = ───
35
[ V 6. ]
6.5 Daar is 35 leerling in die klas
en dus is die totale
moontlike uitkomstes = 35
Daar is 9 leerlinge wat nie
aan sport deelneem nie
en dus is die totale aantal
susesvolle uitkomste = 9
9
P(nie sport) = ───
35
[ V 6. ]
6.6 Daar is 35 leerling in die klas
en dus is die totale
moontlike uitkomstes = 35
Daar is 0 leerlinge wat
sokker speel en dus is die
totale aantal
susesvolle uitkomste = 0
0
P(sokker) = ───
35
= 0
[ V 6. ]
6.7 Daar is 35 leerling in die klas
en dus is die totale
moontlike uitkomstes = 35
Daar is 11 leerlinge wat
krieket speel en dus is daar
35 - 11 = 24 wat nie krieket
speel nie en dus is die
totale aantal
susesvolle uitkomste = 24
OF
Daar is 15 + 9 = 24 leerlinge
wat nie krieket speel nie en
dus is die totale aantal
susesvolle uitkomste = 24
24
P(sokker) = ───
35
[ V 6. ]
6.1 There are 35 pupils in the class
and thus the total
probabile outcomes = 35
There are 19 girls in the class
and thus the
total favourable outcomes = 19
19
P(girl) = ───
35
[ Q 6. ]
6.2 There are 35 pupils in the class
and thus the total
probabile outcomes = 35
There are 15 pupils that play
tennis and thus the
total favourable outcomes = 15
15
P(tennis) = ───
35
3
= ───
: simplify
5
[ Q 6. ]
6.3 There are 35 pupils in the class
and thus total the
total probabile outcomes = 35
There are 11 - 6 = 5 girls that
play cricket and thus the
total favourable outcomes = 5
5
P(girl + cricket) = ───
35
3
= ───
: simplify
5
[ Q 6. ]
6.4 There are 35 pupils in the class
and thus the total the
probabile outcomes = 35
There are 9 - 3 = 6 boys that
do not play any sport and thus the
total favourable outcomes = 6
6
P(boy + no sport) = ───
35
[ Q 6. ]
6.5 There are 35 pupils in the class
and thus the total
probabile outcomes = 35
There are 9 pupils that do not
play any sport and thus the
total favourable outcomes = 9
9
P(no sport) = ───
35
[ Q 6. ]
6.6 There are 35 pupils in the class
and thus the total
probabile outcomes = 35
There are 0 pupils that play
soccer and thus the
total favourable outcomes = 0
0
P(soccer) = ───
35
= 0
[ Q 6. ]
6.7 There are 35 pupils in the class
and thus the total
probabile outcomes = 35
There are 11 pupils that play
cricket and thus there is
35 - 11 = 24 that do not play cricket
and thus the total
favourable outcomes = 24
OR
There are 15 + 9 = 24 pupils that do
not play cricket and thus
the total
favourable outcomes = 24
24
P(not cricket) = ───
35
[ Q 6. ]
7.1 Daar is 10 balle in die sak en
en dus is die totale
moontlike uitkomstes = 10
Daar is 3 blou balle in die sak
en dus is die totale aantal
susesvolle uitkomste = 3
3
P(blou) = ───
10
[ V 7. ]
7.2 Daar is 10 balle in die sak en
en dus is die totale
moontlike uitkomstes = 10
Daar is 2 geel balle in die sak
en dus is die totale aantal
susesvolle uitkomste = 2
2 1
P(geel) = ─── = ──
10 5
[ V 7. ]
7.3 Totale moontlike uitkomste = 10
Daar is 4 rooi balle in die sak
en dus is die totale aantal
susesvolle uitkomste = 4
4 2
P(rooi) = ─── = ──
10 5
[ V 7. ]
7.4 Totale moontlike uitkomste = 10
Daar is geen groen balle in die sak
nie en dus is die totale aantal
susesvolle uitkomste = 0
0
P(groen) = ─── = 0
10
[ V 7. ]
7.5 Totale moontlike uitkomste = 10
Daar is 1 wit, 3 blou en 4 rooi balle
in die sak en dus is die totale aantal
susesvolle uitkomste = 8
8 4
P(nie geel) = ─── = ──
10 5
[ V 7. ]
OF
Totale moontlike uitkomste = 10
Daar is 2 geel balle in die sak en
dus is daar 10 - 2 = 8 nie geel
balle in die sak en is die totale
aantal susesvolle uitkomste = 8
8 4
P(nie geel) = ─── = ──
10 5
[ V 7. ]
OF
P(nie geel) = 1 ─ P(geel)
2
P(nie geel) = 1 ─ ───
10
8 4
= ─── = ──
10 5
[ V 7. ]
7.6 Totale moontlike uitkomste = 10
Daar is 1 wit bal in die sak
en dus is die totale aantal
susesvolle uitkomste = 1
1
P(wit) = ───
10
[ V 7. ]
7.7 Daar is nou geen wit balle
in die sak nie.
[ V 7. ]
7.8 Daar is 9 balle in die sak sodat
totale moontlike uitkomste = 9
[ V 7. ]
7.9 Die waarskynlikheid sal groter word
omdat daar minder balle in die sak is
maar die aantal blou balle bly dieselfde.
[Die teller bly dieselfde maar die
noemer word kleiner en dus
word die breuk groter]
[ V 7. ]
7.10 Totale moontlike uitkomste = 9
Daar is 3 blou balle in die sak
en dus is die totale aantal
susesvolle uitkomste = 3
3 1
P(blou) = ─── = ──
9 3
Dit bevestig my antwoord in 7.9.
[ V 7. ]
7.11 Totale moontlike uitkomste = 9
Daar is geen wit balle in die sak
nie en dus is die totale aantal
susesvolle uitkomste = 0
0
P(wit) = ─── = 0
9
[ V 7. ]
7.12 Totale moontlike uitkomste = 9
Daar is 4 rooi balle in die sak
en dus is die totale aantal
susesvolle uitkomste = 4
4
P(rooi) = ───
9
[ V 7. ]
7.1 There are 10 balls in the bag
and thus the total
probabile outcomes = 10
There are 3 blue balls in the bag
and thus the
total favourable outcomes = 3
3
P(blue) = ───
10
[ Q 7. ]
7.2 There are 10 balls in the bag
and thus the total
probabile outcomes = 10
There are 2 yellow balls in the bag
and thus the
total favourable outcomes = 2
2 1
P(yellow) = ─── = ──
10 5
[ Q 7. ]
7.3 Total probabile outcomes = 10
There are 4 red balls in the bag
and thus the
total favourable outcomes = 4
4 2
P(red) = ─── = ──
10 5
[ Q 7. ]
7.4 Total probabile outcomes = 10
There no green balls in the bag
and thus the
total favourable outcomes = 0
0
P(green) = ─── = 0
10
[ Q 7. ]
7.5 Total probabile outcomes = 10
There are 1 white, 3 blue and 4 red
balls in the bag and thus the
total favourable outcomes = 8
8 4
P(not yellow) = ─── = ──
10 5
[ Q 7. ]
OR
Total probabile outcomes = 10
There are 2 yellow balls in the bag
thus there are 10 ─ 2 = 8 not yellow
balls in the bag and thus the
total favourable outcomes = 8
8 4
P(not yellow) = ─── = ──
10 5
[ Q 7. ]
OR
P(not yellow) = 1 ─ P(yellow)
2
P(not yellow) = 1 ─ ───
10
8 4
= ─── = ──
10 5
[ Q 7. ]
7.6 Total probabile outcomes = 10
There is 1 white ball in the bag
and thus the
total favourable outcomes = 1
1
P(white) = ───
10
[ Q 7. ]
7.7 There are now no white balls
in the bag.
[ Q 7. ]
7.8 There are 9 balls in the bag so that
total favourable outcomes = 9
[ Q 7. ]
7.9 The probability will increase because
there are fewer balls in the bag but the
number of blue balls remained the same.
[The numerator remained the same
but the denominator increased and
thus the fraction becomes greater.]
[ Q 7. ]
7.10 Total probabile outcomes = 9
There are 3 blue balls in the bag
and thus the
total favourable outcomes = 3
3 1
P(blue) = ─── = ──
9 3
This confirms my answer in 7.9.
[ Q 7. ]
7.11 Total probabile outcomes = 9
There no white balls in the bag
and thus the
total favourable outcomes = 0
0
P(green) = ─── = 0
10
[ Q 7. ]
7.12 Total probabile outcomes = 9
There 4 red balls in the bag
and thus the
total favourable outcomes = 4
4
P(red) = ───
9
[ Q 7. ]
8.1 A = 150 ─ (36 + 46 + 19)
= 49
[ V/Q 8. ]
8.1 C = 36 + 57
= 93
[ V/Q 8. ]
8.1 E = 19 + 14
= 33
[ V/Q 8. ]
8.2.1 Die totale aantal leerlinge is 280
en dus is die totale
moontlike uitkomstes = 280
82 leerlinge kom per motor en dus
totale susesvolle uitkomste = 82
82 41
P(per motor) = ─── = ───
280 140
[ V 8. ]
8.2.2 Die totale aantal Graad 8
leerlinge is 150
totale moontlike uitkomstes = 150
19 Graad 8's kom per taxi en dus
totale susesvolle uitkomste = 19
19
P(8 per taxi) = ────
150
[ V 8. ]
8.2.3 Die totale aantal Graad 9
leerlinge is 130
totale moontlike uitkomstes = 130
26 Graad 9's kom per bus en dus
totale susesvolle uitkomste = 26
26 1
P(9 per bus) = ──── = ───
130 5
[ V 8. ]
8.2.4 Die totale aantal Graad 8
leerlinge is 150
totale moontlike uitkomstes = 150
36 Graad 8's het gestap en dus
totale susesvolle uitkomste = 36
36 6
P(8 + stap) = ──── = ───
150 25
[ V 8. ]
8.2.5 Die totale aantal Graad 9
leerlinge is 130
totale moontlike uitkomstes = 130
Geen Graad 9's het gefiets nie en dus
totale susesvolle uitkomste = 0
0
P(9 per fiets) = ──── = 0
130
[ V 8. ]
8.2.1 Die totale aantal leerlinge is 280
en dus is die totale
moontlike uitkomstes = 280
Geen leerling kom per treim en dus
totale susesvolle uitkomste = 0
0
P(per trein) = ─── = 0
280
[ V 8. ]
8.1 B = 130 ─ (57 + 26 + 14)
= 33
[ V/Q 8. ]
OF / OR
B = 82 ─ 49 . . . A
= 33
[ V/Q 8. ]
8.1 D = 46 + 26
= 72
[ V/Q 8. ]
8.1 F = 150 + 130
= 280
[ V/Q 8. ]
8.2.1 The total number of pupils is 280
and thus the total
probabile outcomes = 280
82 pupils came by car and thus
the total favourable outcomes = 82
82 41
P(by car) = ──── = ────
280 140
[ Q 8. ]
8.2.2 The total number of Grade 8
pupils is 150
total probabile outcomes = 150
19 Grade 8 pupils came by taxi and
thus total favourable outcomes = 19
19
P(8 by taxi) = ─────
150
[ Q 8. ]
8.2.3 The total number of Grade 9
pupils is 130
total probabile outcomes = 130
26 Grade 9 pupils came by bus and
thus total favourable outcomes = 26
26 1
P(9 by bus) = ───── = ───
130 5
[ Q 8. ]
8.2.4 The total number of Grade 8
pupils is 150
total probabile outcomes = 150
36 Grade 8 pupils walked and
thus total favourable outcomes = 36
36 6
P(8 + walk) = ───── = ───
150 25
[ Q 8. ]
8.2.5 The total number of Grade 9
pupils is 130
total probabile outcomes = 130
No Grade 9 pupils bicycled to school
thus total favourable outcomes = 0
0
P(9 by bicycle) = ───── = 0
130
[ Q 8. ]
8.2.6 The total number of pupils is 280
and thus the total
probabile outcomes = 280
No pupils came by train and thus
the total favourable outcomes = 0
0
P(by train) = ──── = 0
280
[ Q 8. ]
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